You did notice that's all break-in oil and that's from assembly correct? Coyote doesn't use copper in the bearings.
Will Thinner Oils Damage Your Engine?
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You did notice that's all break-in oil and that's from assembly correct? Coyote doesn't use copper in the bearings.
Aaah, I see that now ... thanks for pointing that out.
The original video is great, but I just read an article (from looking up this new GF6 0w16 oil stuff) and the claim is that 0w16 is 2% better than 0w20, all in the name of lowering carbon footprint. The vid said only about 0.5% between 0w20 to a 5w20.
So, perhaps some clarity is needed?
The vid also has some snafu's in it. Near the end "the piston stops moving for a brief moment". No, not really, and,,,,,,,,, yes, the moving piston can always be in a "stopped" state, just take delta-t to zero and voila, piston is stopped even though it's still moving. Funny how math and physics play together.
So, perhaps some clarity is needed?
The vid also has some snafu's in it. Near the end "the piston stops moving for a brief moment". No, not really, and,,,,,,,,, yes, the moving piston can always be in a "stopped" state, just take delta-t to zero and voila, piston is stopped even though it's still moving. Funny how math and physics play together.
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Ray Boehringer, who died in 2016, developed Frigid-Go while he was at Emery.
At one time he was Chairman of Cincinnati's ASLE chapter.
His name appears on numerous patents for both Emery and Dubois Chemical, another Cincinnati-area chemical manufacturer. He was a real gentleman, a scout leader, and devout Christian.
My memory of the Hatco product was it was a 10W-30 diester developed for what was at that time Amzoil, now Amsoil, and was never sold under Hatco’s name unlike Emery’s 0W-20, which was available commercially in Alaska.
I agree.
A piston has to indeed stop moving for a brief moment in order to change direction 180 degrees.
It's always moving.
Pick any non-zero delta-t you want, in that delta-t is a delta-x. Changing directions does not mean it stops, even in a 180.
The metallurgic stretch (elasticity, like an eleastic band) is so small it's likely not measureable by observation. And even so, so small it's insignificant in the context of the vid.
It's always moving.
Pick any non-zero delta-t you want, in that delta-t is a delta-x. Changing directions does not mean it stops, even in a 180.
It has to stop moving vertically if it's going to change direction 180 degrees. It might move a little bit radially or have some tilting movement in the cylinder some because of piston to cylinder clearance, but that's not vertical movement. I'm talking about purely vertical movement.
Doesn't work like that, if you take the time as zero, sure, but this isn't doing that, it literally has to stop moving in one direction, to then reverse, don't even need maths to have those physics work. (They're talking about at top and bottom of travel, not anywhere along the stroke)It's always moving.
Pick any non-zero delta-t you want, in that delta-t is a delta-x. Changing directions does not mean it stops, even in a 180.
The metallurgic stretch (elasticity, like an eleastic band) is so small it's likely not measureable by observation. And even so, so small it's insignificant in the context of the vid.
It's always moving.
Pick any non-zero delta-t you want, in that delta-t is a delta-x. Changing directions does not mean it stops, even in a 180.
The metallurgic stretch (elasticity, like an eleastic band) is so small it's likely not measureable by observation. And even so, so small it's insignificant in the context of the vid.
No, Respectfully you are incorrect on all points
It does work like that. Moving is a velocity vector of speed & direction. The only way to get zero speed is to make delta-t = 0. Recall that picking any time (t) to look at only defines the position along the direction component of the velocity vector, it will not tell you the speed. The only way delta-x is zero is when delta-t is zero, OR, the item is not moving at all (aka, same position for any delta-t), etc.
Please explain, using the math for motion (aka the velocity vector and it's components).
My math shows it's not possible to have dx=0 when dt !=0 for a object in motion. And to prove the object is always in motion just take any non-zero dt and you get a non-zero dx. To be "stopped" means dx=0 for any chosen non-zero dt.
https://en.wikipedia.org/wiki/File:Graph_of_Piston_Motion.png
The red circles (at TDC and BDC twice each per 360 deg of crank revolution) shows where the piston velocity is zero for a minuscule time period.
The red circles (at TDC and BDC twice each per 360 deg of crank revolution) shows where the piston velocity is zero for a minuscule time period.
First, you need a quick learning annex in math, mechanical engineering and applied physics to get primed
Motion (movement in this case) is displacement along an axis, not velocity
It is going at "X" degrees from whatever the axis is- it reaches the finite end of displacement ( technically its in the nano seconds if you want to split hairs) but then it starts again. There is a definitive hard stop when direction stops and reverses.
You are overthinking and under understanding
It's velocity.
....and changing velocity all the time due to COS function of the rotation part of the crank that directly connects to the linear motion via a connection rod.
The piston also stops at all times (t) (when you set dt=0), and dt=0 only tells us the position and nothing about speed or direction of the velocity vector.
There is no "stop". Speed may be zero at some time (t), but nothing has stopped. The COS function has no stops in it, none. The only way the pistons stop is whe the crank stops rotating, aka engine is turned off.
The vid brought up the subject, I call that false in the vid.
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I think you're missing the part where we're talking about where the piston stops moving upwards, and starts moving downward in the opposite direction.
V = dD/dt (D = distance, t = time)
Bold part of your post isn't true. If D = 0 for any given amount of time, then V = 0 for that period of time.
If D = 0 for a 1/100th of a microsecond (at TDC and BDC), then V = 0. Time never stops in a dynamic system.
It's velocity.
....and changing velocity all the time due to COS function of the rotation part of the crank that directly connects to the linear motion via a connection rod.
The piston also stops at all times (t) (when you set dt=0), and dt=0 only tells us the position and nothing about speed or direction of the velocity vector.
There is no "stop". Speed may be zero at some time (t), but nothing has stopped. The COS function has no stops in it, none. The only way the pistons stop is whe the crank stops rotating, aka engine is turned off.
The vid brought up the subject, I call that false in the vid.
You are fundamentally and fatally flawed in your understanding
nor to be caught in nanoseconds You pulled in a rate equation. How does this apply?
Distance = x1 - x0 = dx
How can there be a dx=0 for some dt when the COS function proves that wrong.
You may see almost no dx from using tools when piston is BTDC TDC and ATDC, but that's because the tools are not good enough.
If the crank is moving the pistons too are ALWAYS moving.
If you had a D=0 for any peiod of time, then after that small period of time the piston is then lagging behind the crank. Hmmm, so after 1,000 crank turns the piston is 1000 x D behind the crank motion. When does the piston catch up? Simply cannot be, the piston is tied to the crank with a very strong rod that never ever leaves it's mounting points.
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