Originally Posted by gathermewool
I don't understand how a blown water heater element would cause an increase in consumption DUE TO the other element having to work harder.
A water heater wants to maintain a temperature and, if one element is gone, should use less energy, if one element couldn't or will barely keep up, right?
That is, unless the failure mode is a short in the heater element near the outside of the tank, so that consumption remains high, though little of that heat is input into the tank.
A typical water heater will have two heating elements, one bottom and one on top. If the bottom element burns out, the top one works harder heating the water. As the bottom element heats the water, the top one will shut off after a while. Hot water rises.
So if the bottom one quits, it would take who knows how long, for the top element to heat the whole tank......if it ever did. That's why it works harder.
I don't understand how a blown water heater element would cause an increase in consumption DUE TO the other element having to work harder.
A water heater wants to maintain a temperature and, if one element is gone, should use less energy, if one element couldn't or will barely keep up, right?
That is, unless the failure mode is a short in the heater element near the outside of the tank, so that consumption remains high, though little of that heat is input into the tank.
A typical water heater will have two heating elements, one bottom and one on top. If the bottom element burns out, the top one works harder heating the water. As the bottom element heats the water, the top one will shut off after a while. Hot water rises.
So if the bottom one quits, it would take who knows how long, for the top element to heat the whole tank......if it ever did. That's why it works harder.