Steam Turbine Failure South Africa

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"CENTRIFUGAL FORCE.
this is the force that is used by a centrifuge to seperate substances of different desnities, for example cream from milk. It is also the force utilised by a sling shot. If a stone is attached to a piece of string and whirled around, the string is pulled taut by the centrifugal force. An equal and opposite force, the centripetal force, is supplied by the string. "

-The Australian Weather book by Colls and Whitaker. 1990.

Seems pretty simple to me. Centrifugal force is needed to keep a body in a circular pattern around a centre. THe centripetal force is the opposite by definition.
 
When you mash the accelerator at the stop light, there is no force "pushing you back in your seat", and thus you accelerate.

When you hit the corner, there is no force "flinging you out".

If either are/were/had an "equal and opposite", then you neither accelerate from the lights, nor stray from a straight path (into circular motion)
 
a stone going around at the end of a string is accelerating because it's direction is constantly changing. it's called centripetal acceleration. hence the force must exist.

you can't tell the difference between gravity and being spun around. that's why rotating donut space stations work in SF land. if you're walking on the floor it feels like gravity. You are being accelarated because velocity is a vector (magnitude of velocity stays the same but direction constantly chaning).

i find it hard to follow or believe your argument. it seems you are obfuscating the issue.
 
Originally Posted By: crinkles
Shannow said:
When you mash the accelerator at the stop light, there is no force "pushing you back in your seat", and thus you accelerate.


of course there is a force, how else would you accelerate? the seat exerts a force on you, and you exert a reaction back onto the seat, otherwise you will start moving spontaneously off the seat! the froce from friction on the tyres is pushing the car and you forward as one, hence you exert a force on the seat and the seat onto you. FWIW the road feels friction one way and the tyre friction the other way. otherwise your tyres would slip? the net force that accelerates the car comes in at the torque applied to the driveaxle, that makes the car go forward.

Originally Posted By: Shannow

When you hit the corner, there is no force "flinging you out".


of course there is, again same deal, the sides of the seat has a force onto you and you react with a froce exaclt the same... otherwise you'll end up in the passenger seat. the net force that makes the car turn and accelerate (centripetally...) is the front wheel force vector which has a component that is out of the plane of force of the rear wheels (lets assume a 4wd car) and hence the combination of you and the car accelerate sideways/centripetally.

Originally Posted By: Shannow

If either are/were/had an "equal and opposite", then you neither accelerate from the lights, nor stray from a straight path (into circular motion)
 
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In your walking around the space station, the centripetal force is the space station continuing to get in your way, and make you "climb" out...There is no force acting on you to the outside...your body wants to go straight, the space station stops you.

If it weren't for the space station walkway accelerating you "inward", you would fly off into space at WxR, your peripheral velocity and at the direction that you were going when you "stepped into the hole"
 
Originally Posted By: Shannow
In your walking around the space station, the centripetal force is the space station continuing to get in your way, and make you "climb" out...There is no force acting on you to the outside...your body wants to go straight, the space station stops you.

If it weren't for the space station walkway accelerating you "inward", you would fly off into space at WxR, your peripheral velocity and at the direction that you were going when you "stepped into the hole"


you're not climbing out anywhere. the floor is accelerating you towards the centre of rotation. you can be accelerated at a constant velocity, because a change in direction needs acceleration (velocity is a vector). the floor exerts a force on your feet. your feet exert a force on the floor. otherwise you would float off the floor. the force from your feet points out to space, the force from the floor points to the centre of rotation. so you stand still with reference to the floor. BOTH forces exist.
 
Originally Posted By: Shannow
When you mash the accelerator at the stop light, there is no force "pushing you back in your seat", and thus you accelerate.


You do not acknowledge that two different forces can act on the same body simultaneously.

Again I resort to the steel wire by which a bucket of concrete is suspended from a crane.

In order for the steel wire to be under tension, two opposite forces must tug at each end.

The normal force from the crane's hook tugs on the steel wire at one end and the bucket's weight tugs on it at the other.

What, because the bucket is heavy the steel wire can't hold it up? Or the crane can't lift it?

Originally Posted By: Shannow
When you hit the corner, there is no force "flinging you out".


No but there is a force pushing you in the side supports of your seat.

Originally Posted By: Shannow
If either are/were/had an "equal and opposite", then you neither accelerate from the lights, nor stray from a straight path (into circular motion)


The inertial force you demonstrably exert on the car seat in any given instant is:

Instantaneous acceleration of car x mass of your body.

Why do you keep claiming the forces must be equal? The force accelerating the entire car already paid for your inertia as well. That doesn't mean you're not exerting an inertial force against your seat. That is demonstrably and measurably false.
 
"The acceleration, hence also the force acting on a body in uniform circular motion, is directed toward the center of the circle; that is, it is centripetal – the so called 'centrifugal force' appearing to act outward on a body is really a pseudo force experienced in the frame of reference of the body in circular motion, due to the body's linear momentum at a tangent to the circle."

from wiki. i know, i know, crucify me later.
 
Originally Posted By: onion
I gave up reading around page 6. Now on page 10 this ridiculous argument is still going.

IMO, this is an argument about semantics and conventions. If ya'll all sat down with a big piece of paper, organized your thoughts, and started drawing forces- I think you'd come to an agreement soon enough.

Personally I think it's a little silly to say that "centrifugal force doesn't exist". That's a matter of semantics and convention. Shannow- you asked for a FBD. Picture this:

Imagine that tether-ball twirling around on a string. The only force you'll see on a FBD of that ball is centripetal force- I'll grant you that. But now consider a FBD of the point where the string attaches to the ball (we'll call it Point A). You have centripetal force (from the string) pulling Point A towards the axis of rotation. But you also have an equal and opposite force pulling Point A AWAY from the axis of rotation (from the ball).

Now this is a matter of semantics... but is it entirely unreasonable to call the force exerted by the ball onto Point A "centrifugal force"? That's exactly what your Average Joe would call it. And it's in the direction that your Average Joe would expect centrifugal force to be in. And it's a result of spinning an object around.

Looks like a duck. Walks like a duck. Quacks like a duck. You might say it's mis-named... but it certainly DOES exist.



Shannow- refer back to 'Point A' in this post of mine. We're in agreement on 'centripetal force'. What are you going to call the opposite force on 'Point A' exerted by the ball- if not 'centrifugal force'?

Even if you don't want to call it that... why can't I? Why is it incorrect to call the force exerted BY the ball 'centrifugal force'?
 
I have a great book here that puts this all in the right perspective.

Shannow is right, centrifugal force does not exist, but there is a lot of wording in this thread that obfuscates the issue.

The only actual force that may properly be called a centrifugal force is the tension on the string exerted by the stone. the stone does not feel a centrifugal force.

the confusion comes in when you are making a dynamic problem into a static problem and viewing the issue from the reference frame of the particle being swung around.
 
copyright statement: From Meriam and Kraige - Engineering mechanics - dynamics, 4th ed.

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Originally Posted By: crinkles
I have a great book here that puts this all in the right perspective.

Shannow is right, centrifugal force does not exist, but there is a lot of wording in this thread that obfuscates the issue.

The only actual force that may properly be called a centrifugal force is the tension on the string exerted by the stone. the stone does not feel a centrifugal force.


the confusion comes in when you are making a dynamic problem into a static problem and viewing the issue from the reference frame of the particle being swung around.


I can buy that argument. Like I've said- we've been arguing for 10 pages over semantics and convention.

I agree with the text you posted. There is no centrifugal force acting on the particle. But that doesn't mean that the force "doesn't exist" depending on your frame of reference.

'Cause if I choose my rather arbitrary frame of reference and isolate the point where the string attaches to the tetherball- at that point there IS a force that you could rightly call "centrifugal force". Maybe some folks don't like that name... nor may they prefer that frame of reference. But it's just plain obtuse to say that said force "doesn't exist".
 
It's somehow appropriate that a discussion of rotational motion is now going around in circles
grin.gif


Originally Posted By: crinkles
"The acceleration, hence also the force acting on a body in uniform circular motion, is directed toward the center of the circle; that is, it is centripetal – the so called 'centrifugal force' appearing to act outward on a body is really a pseudo force experienced in the frame of reference of the body in circular motion, due to the body's linear momentum at a tangent to the circle."

from wiki. i know, i know, crucify me later.

No, this is great. Some of words in that quote (italicized by me) should point you in the direction of the truth. "So called" and "psuedo" pretty much sums it up. It's not real. Go ahead and look it up on Wikipedia, it'll bring up the page on fictitious forces. Go down to the section on circular motion and you'll see this quote:

"A classic example of fictitious force in circular motion is the experiment of rotating spheres tied by a cord and
spinning around their center of mass. In this case, as with the linearly accelerating car example, the identification of a rotating, non-inertial frame of reference can be based upon the vanishing of fictitious forces. In an inertial frame, fictitious forces are not necessary to explain the tension in the string joining the spheres. In a rotating frame, Coriolis and centrifugal forces must be introduced to predict the observed tension."

Quote:
Shannow- refer back to 'Point A' in this post of mine. We're in agreement on 'centripetal force'. What are you going to call the opposite force on 'Point A' exerted by the ball- if not 'centrifugal force'?

Even if you don't want to call it that... why can't I? Why is it incorrect to call the force exerted BY the ball 'centrifugal force'?

onion, it's not a matter of semantics - it's a matter of science and using the correct terms to explain things. You reference "average Joe" earlier - I recall the quote I provided a couple pages ago - ""...but because the human mind has such a strong inclination to perceive inertia as a force in itself, it needs to be clarified in the most basic terms." The very specific language used by scientists is necessary to avoid the types of misunderstandings the Average Joe is inclined to make!

jeff

crinkles I see you have found a suitable reference
cheers3.gif
 
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It's not plain obtuse to exclude an apparent force...the force exerted on you by your seat to make you change direction !!!

If you have a horizontal shaft rotating machine and have to introduce a rotating gravitational force to get your math to work ???...That's obtuse...and about as obtuse as it can get.
 
Semantics and convention. Ya'll have only demonstrated why the convention you use is preferable- and I'm not arguing that point. It IS more convenient.

But none of ya'll have explained away the centrifugal force on 'point A' in my tether-ball example. It's exerted BY the ball. It opposes centripetal force from the string. It's exactly what people are describing when they talk about "centrifugal force".

Like I've said too many times: You may not like the frame of reference I'm using. It may well be mathematically inconvenient. But that force exists, and ya'll haven't shown otherwise.
 
Originally Posted By: onion
But none of ya'll have explained away the centrifugal force on 'point A' in my tether-ball example. It's exerted BY the ball. It opposes centripetal force from the string. It's exactly what people are describing when they talk about "centrifugal force".

What you're describing is the reaction force between the ball and the string - standard newton's 3rd law stuff, defined as F=m*v^2/r. The critical distinction, which you make and which is the key point for the topic at hand (a steam turbine blowing apart), is that that reaction force is not being applied to the ball itself, but rather by the ball. The apparent "outward" motion of the ball (or the exploding turbine parts) has absolutely nothing to do with that "centrifugal" force - yet that is exactly what is commonly (and mistakenly) used to explain it.

jeff
 
Originally Posted By: onion
Semantics and convention. Ya'll have only demonstrated why the convention you use is preferable- and I'm not arguing that point. It IS more convenient.

But none of ya'll have explained away the centrifugal force on 'point A' in my tether-ball example. It's exerted BY the ball. It opposes centripetal force from the string. It's exactly what people are describing when they talk about "centrifugal force".

Like I've said too many times: You may not like the frame of reference I'm using. It may well be mathematically inconvenient. But that force exists, and ya'll haven't shown otherwise.


This isn't a discussion on semantics, it's on principles. And the mathematical convenience is not the issue (we use constructs like massless strings to make the math easier for the noobs...). We've got to get a shared undertanding of the basics to move on and explain the questions you're asking. Actually, it's Pseudo Forces that make the math easy, that's why engineers use them for calculations of things like drag...but we're not to that point yet. We have to get to an understanding of the three laws of motion and pseudo forces, which I have already explained in detail. And you can't just choose a new reference frame without understanding what takes place in every reference frame. So let's drop the reference frame consideration for now, it's complicating the discussion.

The definitions are central to understanding. If you really want to understand the physical world, it's physics that describes it, not comforting notions of perception, and you have to use the terms correctly or we're talking past each other...I didn't take this out of the layman's realm, but we are out of the layman's realm now. If we are more comfortable back there, then yes, it's turtles all the way down and centrifugal force tore the turbine apart...if that's not the path y'all want, then read on...

When I have a bit more time, I'll explain how one applied force (not tension, but the centripetal acceleration) can tear a turbine apart. Maybe we'll even get to how an airplane works and why the engineers that design them choose a non-inertial reference frame (hint: it's to make the math EASIER...physics is hard, even engineers struggle with it sometimes...) Look, Physics isn't easy, I had 2 years of Newtonian mechanics in High School, then majored in Physics in college...it took me years to gain the understanding that I am trying to impart (with admittedly little success...) here.

For now, let's get to Newton's third law of motion as we proceed down the path of physics.

You're "feeling" a force when you swing the ball, but what you're feeling is not the ball pulling...it's YOU pulling the ball...I never got to Newton's 3rd law (for every action there is an equal and opposite reaction). The 3rd law is one that is confusing to most folks.

The tether ball is a great example - everyone keeps saying "who cares where it goes if the string breaks?" but that is the quintessence of the question. The ball only moves because it is being PULLED by the string. It goes in a circle because it is in accelerated (circular) motion constantly. If the string breaks, then we're back to Newton's first law - the ball moves in an inertial path.

If there are two equal and opposite forces on an object, (remember that forces are vectors, not scalars, they have direction as well...) then they cancel each other out. There is no NET force. Since a force, by definition, imparts an acceleration, if you had two, equal and opposite forces (centripetal and centrifugal), then there would be NO acceleration towards the center and the ball would proceed on an inertial path. So, there simply can't be an opposite (or equivalent) force. There are only pseudo forces - those things that satisfy human perception. In order to impart a force, we have to keep in mind Newton's third law (for every action there is an equal and opposite reaction). The ball isn't "pulling" on me - I am imparting a force to it. Not semantically important but critically important for understanding.

So, forget for a moment that the ball is going in a circle. Picture a rock on a hockey rink (as close to frictionless as we can get..). Tie a string to it (strong, but zero weight, so we can ignore the force that you have to impart to the string itself and focus on the rock). You pull the string - the rock accelerates. Its velocity changes only as long as you pull on the string. Once you stop pulling the rock is sliding with a direction and a speed. Newton's first law...it will stay sliding (again, work with me, this is a frictionless rink...we all know that friction is not zero even on a rink...).

If you want to change that direction and speed - you pull on the string, could be same direction, doesn't have to be, and we're back to Newton's Second law - you impart a force - you change the rock's velocity. Your force is measured as a function of mass (the rock) times acceleration (change in rock's velocity). you don't have to pull the string in the same direction, it can be in any direction and you are imparting a force. Definition of a force was covered in my first lesson.

If you pulled on the string very gently (small F), then the A will be very small too...that's how ion thrusters on satellites work, micro newtons of thrust (very small F, very very small A) - over a long time and you get big changes in V, but that's impulse (force over time) and we're not ready to get to that yet.

In fact, here's one of the interesting things - I can accomplish that same acceleration using Newton's third law. This is how rockets work. Before the first rockets flew into space, engineers and scientist passionately argued that they could not fly without something to "push" against. We know that's not true, but the argument that the rocket has to "push" against the air is precisely the same argument as the equivalent force and the reality of pseudo forces.

But the third law is more elegant and simple than the pseudo force argument. Rocket propellant goes out the back of the rocket. The rocket moves the other way. Energy must be conserved. We can do this with a big rock on our hockey rink. If I stand on that big rock and throw a Brick, then rock and I move the opposite direction (3rd law). If I have a lot of bricks, and Roger Clement's arm... I can keep throwing them and the rock and I will acclerate in the opposite direction because I imparted a force on that thrown rock and the opposite reaction force is imparted on me. If I can keep this up...at some point, the rock will be moving faster than the bricks I am throwing, each brick MUST accelerate the rock (3rd law and conservation). That's how Apollo got to the moon - the rocket exhaust was about 5-10,000 MPH, but the spacecraft ended up going about 25,000 MPH - escape velocity for lunar insertion.

There is no "equivalent force" for my brick throwing or rocket exhaust. There can't be, if there was something acting on the rocket besides what I have described, it wouldn't work...it wouldn't accelerate enough to get to the moon (or even into orbit). And there is no drag in space to complicate the math or principles...there is only the 2nd law, F=MA, 3rd law, and conservation.

And they work perfectly and completely to describe the motion.

Here ends the seventh lesson in Physics.
 
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Originally Posted By: maersk
Originally Posted By: Shannow
When you mash the accelerator at the stop light, there is no force "pushing you back in your seat", and thus you accelerate.


You do not acknowledge that two different forces can act on the same body simultaneously.

Again I resort to the steel wire by which a bucket of concrete is suspended from a crane.

In order for the steel wire to be under tension, two opposite forces must tug at each end.

The normal force from the crane's hook tugs on the steel wire at one end and the bucket's weight tugs on it at the other.

What, because the bucket is heavy the steel wire can't hold it up? Or the crane can't lift it?

Originally Posted By: Shannow
When you hit the corner, there is no force "flinging you out".


No but there is a force pushing you in the side supports of your seat.

Originally Posted By: Shannow
If either are/were/had an "equal and opposite", then you neither accelerate from the lights, nor stray from a straight path (into circular motion)


The inertial force you demonstrably exert on the car seat in any given instant is:

Instantaneous acceleration of car x mass of your body.

Why do you keep claiming the forces must be equal? The force accelerating the entire car already paid for your inertia as well. That doesn't mean you're not exerting an inertial force against your seat. That is demonstrably and measurably false.


In the same sentance, you claim that the forces must be equal and must not be equal. Both statements can't be right...

In fact, while you "feel" the Pseudo force, there is only one force acting - the force that changes your direction...remember, we're describing motion here...not static tension of a hanging bucket. Don't confuse the issue (or yourself) by using the word "force" ambiguously...stick with the force definition from lessons 1 and 2.

Newton's second law of motion applies. A force acts on you to continuously change your velocity (direction of motion).

In the case of the bucket there is no NET force - it is static - it is hanging without acceleration....so we're not talking about motion....F=MA. If A=0, then the other side of the equation (F) must also be zero!

This is why the definitions and principles matter so much.
 
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