converting percentage % to ppm, and ZDDP ???

Status
Not open for further replies.
Joined
Jul 20, 2007
Messages
3,742
Location
Northern California, USA
(This is about 2-stroke oil, but I thought I would post it here because it gets more sight seeing traffic.)

I was looking at the Pennzoil XLF 2-stroke oil MSDS and it showed the following information:

Chemical Identity ------------- CAS No. --- Concentration
Zinc alkyl dithiophosphate -- 68649-42-3 -- 1.00 - 5.00 %

further down the sheet it says:

SARA Toxic Release Inventory (TRI) (313)
Zinc alkyl dithiophosphate (68649-42-3) 1.60%

I am guessing this is ZDDP. How many ppm equals 1.60%? I think it is 1600ppm, but I am not sure.

Does ZDDP produce ash residue in the combustion chamber? I was under the impression that metallic compounds that show up in oil analysis cause ash deposits, and ZDDP shows up as Zinc and Phosphorus.



The PDS for this stuff says:

"PENNZOIL MARINE® XLF OUTBOARD TWO-CYCLE OIL contains only ashless components
which helps prevent any lubricant related preignition and spark plug fouling. The ashless
additives
also help protect against piston and combustion chamber deposits, rust, and
corrosion. It’s “anti-gel” properties help resist gel formation due to water or other contamination.
The special base stocks used resist piston and cylinder wall scuffing. "
 
Straight from math, 1.6% = 16000 ppm.
But not sure if that's how they define here.
 
Originally Posted By: lemonade
Straight from math, 1.6% = 16000 ppm.
But not sure if that's how they define here.


That seems like a lot of ZDDP for use in an oil that will most surely be consumed in a combustion chamber.
 
Status
Not open for further replies.
Back
Top