Thought of this discussion as I took off from Maui last night.
Runway 2. 6995' useable runway. 4kts XW. 0HW. 21C. 30.06". 233,300# airplane.
For reduced thrust, of 1.66 EPR, v-speeds were:
V1 135. VR 139. V2 143
For max thrust of 1.77 EPR, v-speeds were:
V1 121. VR 136. V2 143
The takeoff safety speed of V2 is the same, and is really a function of climb performance (which is based in weight, CG, atmospherics, slope, etc.).
But there is a slightly lower VR with more power -which makes sense with a higher acceleration rate. Rotate just a bit sooner to intercept V2.
But here's the key point: with more power on the airplane, and greater acceleration, the decision to go is made SOONER with MORE runway in front of the airplane.
Clearly, with higher thrust, the airplane rotates with more runway remaining. In a balanced field calculation, you would have a higher V1 at higher power. But we don't do balanced field...
In this case, the airplane has the performance to "go" at a lower speed when it has more power. That greater runway in front of it, and the higher engine thrust, allows for an earlier V1 go decision.
With an 80 foot cliff off the end of the runway, I'm OK with biasing towards the go decision...
Cheers,
Astro