I set about to calculate how much power an engine could theoretically produce, assuming the combustion chambers were completely filled with air/fuel mixture, and the air was at atmospheric pressure. I was also interested in what the volumetric air:fuel ratio was (we know the mass ratio is 14.7:1). Here I go...
(engine displacement) = (volume of air) + (volume of fuel)
(volume of air) = (mass of air)/(density of air)
(volume of fuel) = (mass of fuel)/(density of fuel)
substituting these in:
(engine displacement) = (mass of air)/(density of air) + (mass of fuel)/(density of fuel)
substitute in the stoichiometric ratio: (mass of air) = 14.7 * (mass of fuel)
(engine displacement) = (14.7 * mass of fuel)/(density of air) + (mass of fuel)/(density of fuel)
approximate density of gasoline: 0.75kg/L
approximate density of air @ 0C: 0.001294kg/L
let's assume a 2.0L engine
2.0L = (14.7 * mass of fuel)/0.001294kg/L + (mass of fuel)/0.75kg/L
Since dividing by x*kg/L is the same thing as multiplying by 1/x * L/kg,
2.0L = 11360L/kg * (mass of fuel) + 1.333L/kg * (mass of fuel)
Here we can see the volumetric AFR is 11360:1.333, or 8520:1.
Solving for (mass of fuel):
(mass of fuel) = 1.7603*10^-4 kg
Gasoline has 47.2MJ/kg, so this mass of fuel contains 8.31KJ.
Since this amount of fuel would be injected once per revolution, if we assume the engine is spinning at 6000 RPM (100 revolutions per second), it's liberating 831KJ/s, which is equivalent to 1,114 horsepower.
If we assume, the engine is 25% efficient at converting chemical energy to motion, that's still 279hp at the crank.
This is where my question comes in. That's a lot of horsepower! Even if you multiply by 75% to account for volumetric efficiency, that's 209hp. Did I do something wrong, or am I making an incorrect assumption?
Thanks for reading this!
(engine displacement) = (volume of air) + (volume of fuel)
(volume of air) = (mass of air)/(density of air)
(volume of fuel) = (mass of fuel)/(density of fuel)
substituting these in:
(engine displacement) = (mass of air)/(density of air) + (mass of fuel)/(density of fuel)
substitute in the stoichiometric ratio: (mass of air) = 14.7 * (mass of fuel)
(engine displacement) = (14.7 * mass of fuel)/(density of air) + (mass of fuel)/(density of fuel)
approximate density of gasoline: 0.75kg/L
approximate density of air @ 0C: 0.001294kg/L
let's assume a 2.0L engine
2.0L = (14.7 * mass of fuel)/0.001294kg/L + (mass of fuel)/0.75kg/L
Since dividing by x*kg/L is the same thing as multiplying by 1/x * L/kg,
2.0L = 11360L/kg * (mass of fuel) + 1.333L/kg * (mass of fuel)
Here we can see the volumetric AFR is 11360:1.333, or 8520:1.
Solving for (mass of fuel):
(mass of fuel) = 1.7603*10^-4 kg
Gasoline has 47.2MJ/kg, so this mass of fuel contains 8.31KJ.
Since this amount of fuel would be injected once per revolution, if we assume the engine is spinning at 6000 RPM (100 revolutions per second), it's liberating 831KJ/s, which is equivalent to 1,114 horsepower.
If we assume, the engine is 25% efficient at converting chemical energy to motion, that's still 279hp at the crank.
This is where my question comes in. That's a lot of horsepower! Even if you multiply by 75% to account for volumetric efficiency, that's 209hp. Did I do something wrong, or am I making an incorrect assumption?
Thanks for reading this!