Originally Posted By: y_p_w
Originally Posted By: CapriRacer
When I read what I wrote, and applied it to the subject here (winter tires), I realized that winter tires are very likely the exception to the rule - that tread compound DOES play a role in the speed rating.
OK. But what would the mechanism be for that? I thought that belt separation is the primary mechanism where a tire fails during a speed-rating test. For winter tires, would tread failure be the more likely result?
I only looked for that because I remember one of your older posts said that you could probably swap any tread to a certain speed-rated carcass, and it would likely still test for the same speed rating.
I think the failure would still be a belt leaving belt separation, but the hotter running tread compound and the additional tread depth would make the belt edges run hotter - and enough to change the actual step in which the tire failed.
If the tread of a winter tire would be shaved off, likely the tire would pass the standard S or T rating.
Originally Posted By: CapriRacer
When I read what I wrote, and applied it to the subject here (winter tires), I realized that winter tires are very likely the exception to the rule - that tread compound DOES play a role in the speed rating.
OK. But what would the mechanism be for that? I thought that belt separation is the primary mechanism where a tire fails during a speed-rating test. For winter tires, would tread failure be the more likely result?
I only looked for that because I remember one of your older posts said that you could probably swap any tread to a certain speed-rated carcass, and it would likely still test for the same speed rating.
I think the failure would still be a belt leaving belt separation, but the hotter running tread compound and the additional tread depth would make the belt edges run hotter - and enough to change the actual step in which the tire failed.
If the tread of a winter tire would be shaved off, likely the tire would pass the standard S or T rating.
